Given a non-empty set X, let *:P (X)×P (X)\(\to\) P (X) be defined as A * B= (A−B)∪(B−A),∀ A,B∈ P (X).
Show that the empty set \(\Phi\) is the identity for the operation * and all the elements A of P (X) are invertible with \(A^{-1}=A.\)
(Hint: \((A-\Phi)\cup(\Phi-A)=A\,and\,(A-A)\cup(A-A)=A*A=\Phi)\).