If \(\begin{vmatrix}x&2\\18&x\end{vmatrix}=\begin{vmatrix}6&2\\18&6\end{vmatrix}\),then x is equal to
6
±6
-6
0
\(\begin{vmatrix}x&2\\18&x\end{vmatrix}=\begin{vmatrix}6&2\\18&6\end{vmatrix}\)
\(\Rightarrow\) x2-36=36-36
\(\Rightarrow\) x2-36=0
\(\Rightarrow \) x2=36
\(\Rightarrow\) x=±6
Hence, the correct answer is B.
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