If \(\begin{vmatrix}x&2\\18&x\end{vmatrix}=\begin{vmatrix}6&2\\18&6\end{vmatrix}\),then x is equal to
6
±6
-6
0
\(\begin{vmatrix}x&2\\18&x\end{vmatrix}=\begin{vmatrix}6&2\\18&6\end{vmatrix}\)
\(\Rightarrow\) x2-36=36-36
\(\Rightarrow\) x2-36=0
\(\Rightarrow \) x2=36
\(\Rightarrow\) x=±6
Hence, the correct answer is B.
If \(\begin{vmatrix} 2x & 3 \\ x & -8 \\ \end{vmatrix} = 0\), then the value of \(x\) is: