Using the property of determinants and without expanding, prove that: \(\begin{vmatrix}1&bc&a(b+c)\\1&ca&b(c+a)\\1&ab&c(a+b)\end{vmatrix}\)=0
\(\triangle=\begin{vmatrix}1&bc&a(b+c)\\1&ca&b(c+a)\\1&ab&c(a+b)\end{vmatrix}\)
By applying C3 \(\to\) C3 + C2, we have:
\(\triangle=\begin{vmatrix}1&bc&ab+bc+ca\\1&ca&ab+bc+ca\\1&ab&ab+bc+ca\end{vmatrix}\)
Here, two columns C1 and C3 are proportional.
∆ = 0.
A settling chamber is used for the removal of discrete particulate matter from air with the following conditions. Horizontal velocity of air = 0.2 m/s; Temperature of air stream = 77°C; Specific gravity of particle to be removed = 2.65; Chamber length = 12 m; Chamber height = 2 m; Viscosity of air at 77°C = 2.1 × 10\(^{-5}\) kg/m·s; Acceleration due to gravity (g) = 9.81 m/s²; Density of air at 77°C = 1.0 kg/m³; Assume the density of water as 1000 kg/m³ and Laminar condition exists in the chamber.
The minimum size of particle that will be removed with 100% efficiency in the settling chamber (in $\mu$m is .......... (round off to one decimal place).
Read More: Properties of Determinants