Choose the correct answer :
1. The probability that a randomly chosen 2 × 2 matrix with all the entries from the set of first 10 primes, is singular, is equal to :
The number of ways to distribute 30 identical candies among four children C1, C2, C3 and C4 so that C2 receives atleast 4 and atmost 7 candies, C3 receives atleast 2 and atmost 6 candies, is equal to:
g :R→R be two real valued functions defined as\(f(x) = \begin{cases} -|x + 3| & x < 0 \\ e^x, & x \geq 0 \end{cases}\)and\(g(x) = \begin{cases} x^2 + k_1x ,& x < 0 \\ 4x + k_2 ,& x \geq 0 \end{cases}\)where k1 and k2 are real constants. If (goƒ) is differentiable at x = 0, then (goƒ) (–4) + (goƒ) (4) isequal to:
\(\lim_{{x \to \frac{1}{\sqrt{2}}}} \frac{\sin(\cos^{-1}(x)) - x}{1 - \tan(\cos^{-1}(x))}\)is equal to :
If the inverse trigonometric functions take principal values, then\(cos^{-1} ( \frac{3}{10} cos (tan^{-1} (\frac{4}{3})) + \frac{2}{5} sin (tan^{-1} (\frac{4}{3})))\)is equal to :
The normal to the hyperbola\(\frac{x²}{a²} - \frac{y²}{9} = 1\)at the point (8, 3√3) on it passes through the point:
Let z1 and z2 be two complex numbers such that
\(z_1=iz_2 \,and \,arg(\frac{z_1}{z_2})=π.\)
If \(\vec{a}⋅\vec{b}=1,\vec{b}⋅\vec{c}=2 and\) \(\vec{c}⋅\vec{a}=3,\)then the value of[\([\vec{a}×(\vec{b}×\vec{c}),\vec{b}×(\vec{c}×\vec{a}),\vec{c}×(\vec{b}×\vec{a})]\) is
Let the plane 2x + 3y + z + 20 = 0 be rotated through a right angle about its line of intersection with the plane x – 3y + 5z = 8. If the mirror image of the point \((2,−\frac{1}{2},2) \)in the rotated plane is B( a, b, c),then
Let a biased coin be tossed 5 times. If the probability of getting 4 heads is equal to the probability of getting 5 heads, then the probability of getting atmost two heads is
Let\( Δ,▽∈{∧,∨} \)be such that \(p▽q⇒((pΔq)▽r) \)is a tautology. Then \((p▽q)Δr \)is logically equivalent to:
The mean and variance of a binomial distribution are α and α/3, respectively. If P(X = 1) = 4/243 then P(X = 4 or 5) is equal to :
Let\(f(x)=\frac{x−1}{x+1},x∈R− \left\{0,−1,1\right\}\)If ƒn+1(x) = ƒ(ƒn(x)) for all n∈N, then ƒ6(6) + ƒ7(7) is equal to :
The area bounded by the curve \(y=|x^2−9| \)and the line y = 3 is
Let \(f(x)=2cos^{−1}x+4cot^{−1}x−3x^2−2x+10,X∈[−1,1]\)If [a, b] is the range of the function, f then 4a – b is equal to :