\(sin^{-1}\bigg(\frac{\sqrt3}{2}\bigg)+cos^{-1}\bigg(\frac{-\sqrt3}{2}\bigg)+tan^{-1}(-1)\)
= \(\frac{π}{3}+\frac{5π}{6}-\frac{π}{4}\)
= \(\frac{4π+10π-3π}{12}\)
=\(\frac{11π}{12}\)
Hence, the correct option is (A): \(\frac{11π}{12}\)
Let one focus of the hyperbola \( H : \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 \) be at \( (\sqrt{10}, 0) \) and the corresponding directrix be \( x = \dfrac{9}{\sqrt{10}} \). If \( e \) and \( l \) respectively are the eccentricity and the length of the latus rectum of \( H \), then \( 9 \left(e^2 + l \right) \) is equal to:

Various trigonometric identities are as follows:
Cosecant and Secant are even functions, all the others are odd.
T-Ratios of (2x)
sin2x = 2sin x cos x
cos 2x = cos2x – sin2x
= 2cos2x – 1
= 1 – 2sin2x
T-Ratios of (3x)
sin 3x = 3sinx – 4sin3x
cos 3x = 4cos3x – 3cosx