An alkyl halide with molecular formula C$_5$H$_11$Br on dehydrohalogenation gives two isomeric alkenes X and Y with formula C$_5$H$_10$. On reductive ozonolysis, X and Y give four compounds CH$_3$CHO, (CH$_3$)$_2$CHO, CH$_3$CO, HCHO. The alkyl halide is: