The conductivity of a 0.2 M solution of KCl is \( 2.48 \times 10^{-2} \) S cm\(^{-1}\). Calculate its molar conductivity and degree of dissociation (\( \alpha \)).
Given: \( \lambda^0_{\text{K}^+} = 73.5 \, \text{S cm}^2 \text{mol}^{-1} \), \( \lambda^0_{\text{Cl}^-} = 76.5 \, \text{S cm}^2 \text{mol}^{-1} \)