Zn\(^{2+}\) salts are colourless. Why?
Zinc \(^{2+}\) salts are colorless because the \( Zn^{2+} \) ion has a completely filled \( 3d^{10} \) electron configuration. The lack of any unpaired electrons in the \( 3d \) orbitals prevents the absorption of visible light, which is required for color. As a result, zinc salts do not absorb visible wavelengths of light, leading to the colorless appearance of \( Zn^{2+} \) solutions. In other transition metal ions, the unfilled \( d \)-orbitals allow electronic transitions that absorb specific wavelengths of visible light, giving the solution a color. Since \( Zn^{2+} \) does not have such transitions, it remains colorless.
(a) State the following:
(i) Kohlrausch law of independent migration of ions
A solution of glucose (molar mass = 180 g mol\(^{-1}\)) in water has a boiling point of 100.20°C. Calculate the freezing point of the same solution. Molal constants for water \(K_f\) and \(K_b\) are 1.86 K kg mol\(^{-1}\) and 0.512 K kg mol\(^{-1}\) respectively.
Write the reactions involved when D-glucose is treated with the following reagents: (a) HCN (b) Br\(_2\) water
Identify A and B in each of the following reaction sequence:
(a) \[ CH_3CH_2Cl \xrightarrow{NaCN} A \xrightarrow{H_2/Ni} B \]
(b) \[ C_6H_5NH_2 \xrightarrow{NaNO_2/HCl} A \xrightarrow{C_6H_5NH_2} B \]
Would you expect benzaldehyde to be more reactive or less reactive in nucleophilic addition reactions than propanal? Justify your answer.