Acidified KMnO_4 oxidizes sulphite to:
S_2O_8^{2-}
Step 1: Understanding the oxidation reaction. In acidic conditions, potassium permanganate (KMnO_4) is a strong oxidizing agent that oxidizes sulphite (SO_3^{2-}) to sulfate (SO_4^{2-}).
Step 2: Conclusion. Thus, the oxidation product is SO_4^{2-}, corresponding to option (B).
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]
Which element is a strong reducing agent in +2 oxidation state and why?
Propanoic acid to Ethane