List of top Questions asked in Andhra Pradesh Post Graduate Engineering Common Entrance Test

The maximum phase shift that can be provided by a lead compensator with transfer function $ G(s) = \dfrac{1 + 6s}{1 + 2s} $ is:

A thermistor has a resistance of $ 10\,\text{k}\Omega $ at $ 25^\circ\text{C} $ and $ 1\,\text{k}\Omega $ at $ 100^\circ\text{C} $. The range of operation is $ 0^\circ\text{C} $ to $ 150^\circ\text{C} $. The excitation voltage is 5 V and a series resistor of $ 1\,\text{k}\Omega $ is connected to the thermistor. The power dissipated in the thermistor is:

A piezoelectric type accelerometer has a sensitivity of 100 mV/g. The transducer is subjected to a constant acceleration of 5 g. The steady-state output of the transducer will be:

The energy required to charge a $ 10\,\mu\text{F} $ capacitor to $ 100\,\text{V} $ is:

If $R_1 = R_2 = R$ and $R_3 = 1.1R_4$ in the bridge circuit shown in figure, then the reading in the ideal voltmeter connected between $a$ and $b$ is:

In the below circuit, the value of $V_1$ is:

When testing a coil having a resistance of $ 10\,\Omega $, resonance occurred when the oscillator frequency was $ 10\,\text{MHz} $ and the rotating capacitor was set at $ \dfrac{500}{2\pi}\,\text{pF} $. The effective value of the Q of the coil is:

The open-loop voltage gain of an amplifier is 240. The noise level in the output without feedback is 100 mV. If a negative feedback with $ \beta = \dfrac{1}{60} $ is used, the noise level in the output will be:

A differential amplifier has $ R_L = 10\,\text{k}\Omega $ (equal values in both collectors), $ h_{ie} = 1\,\text{k}\Omega $, $ R_e = 50\,\text{k}\Omega $, and $ h_{fe} = 100 $. The common-mode gain is given by:

The op-amp and the 1 mA current source in the circuit of figure are ideal. The output of the op-amp is:

When the switch $S_2$ is closed, the gain of the programmable gain amplifier shown in the following figure is:

For the op-amp circuit shown in the figure below, $V_o$ is:

If the op-amp in figure is ideal, the output voltage Vout will be equal to:

An op-amp has an offset voltage of 1 mV and is ideal in all other respects. If this op-amp is used in the circuit shown in figure below, the output voltage will be (select the nearest value):