Question:

The energy required to charge a \( 10\,\mu\text{F} \) capacitor to \( 100\,\text{V} \) is:

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Use the formula $E = \frac{1}{2} C V^2$ to quickly compute energy stored in capacitors. Always convert $\mu\text{F}$ to farads first.
Updated On: Jun 24, 2025
  • 0.10 J
  • 0.05 J
  • $5 \times 10^{-9}$ J
  • $10 \times 10^{-9}$ J
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The Correct Option is B

Solution and Explanation

The energy stored in a capacitor is given by the formula:
\[ E = \frac{1}{2} C V^2 \]
Where:
\( C = 10\,\mu\text{F} = 10 \times 10^{-6}\,\text{F} \)
\( V = 100\,\text{V} \)

Substitute the values:
\[ E = \frac{1}{2} \times 10 \times 10^{-6} \times (100)^2 = \frac{1}{2} \times 10 \times 10^{-6} \times 10000 = \frac{1}{2} \times 0.1 = 0.05\,\text{J} \] So, the energy required is 0.05 J.
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