List of top Physics Questions asked in AP EAMCET

The semiconductor used for fabrication of visible LEDs must at least have a band gap of:
In a common emitter amplifier, a.c. current gain is 40 and input resistance is 1 kΩ. The load resistance is given as 10 kΩ. Then the voltage gain is:
An information signal of frequency 10 kHz is modulated with a carrier wave of frequency 3.61 MHz. The upper side and lower side frequencies are:
If the maximum and minimum voltages of an A.M wave are \( V_{\max} \) and \( V_{\min} \) respectively, then the modulation factor ‘m’ is
An object is projected such that it has to attain maximum range, while another body is projected to reach maximum height. If both objects reached the same maximum height, then find the ratio of their initial velocities.
A block of mass 5 kg is placed on a rough horizontal surface with a coefficient of friction 0.5. If a horizontal force of 60 N is acting on it, then the acceleration of the block is (Acceleration due to gravity \( g = 10 \) ms\(^{-2}\)):
The potential difference across the ends of a conductor is \( (30 \pm 0.3) V \) and the current through the conductor is \( (5 \pm 0.1) A \). The error in the determination of the resistance of the conductor is:
A body thrown vertically upwards reaches a maximum height \( H \). The ratio of the velocities of the body at heights \( \frac{3H}{4} \) and \( \frac{8H}{9} \) from the ground is:
The equation of projectile motion is given by \( y = 3x - 0.8x^2 \). The time of flight of the projectile is (Acceleration due to gravity \( g = 10 \) m/s²):
A 100 kg gun fires a ball of 1 kg horizontally from a cliff of height 500 m. It falls on the ground at a distance of 400 m from the bottom of the cliff. The recoil velocity of the gun is (Acceleration due to gravity \( g = 10 \) ms\(^{-2}\)):
The average power generated by a 90 kg mountain climber who climbs a summit of height 600 m in 90 minutes is (Acceleration due to gravity \( g = 10 \) m/s\(^2\)):
A boy weighing 50 kg finished a long jump at a distance of 8 m. Considering that he moved along a parabolic path and his angle of jump is \( 45^\circ \), his initial kinetic energy is:
A uniform rod of length \( 2L \) is placed with one end in contact with the earth and is then inclined at an angle \( \alpha \) to the horizontal and allowed to fall without slipping at the contact point. When it becomes horizontal, its angular velocity will be:
A uniform rod of length \( 2L \) is placed with one end in contact with the earth and is then inclined at an angle \( \alpha \) to the horizontal and allowed to fall without slipping at the contact point. When it becomes horizontal, its angular velocity will be:
Two simple harmonic motions are represented by \(y_1 = 5 \left[ \sin 2\pi t + \sqrt{3} \cos 2\pi t \right] \) and \(y_2 = 5 \sin \left[ 2\pi t + \frac{\pi}{4} \right] \). The ratio of their amplitudes is:
When a mass \( m \) is connected individually to the springs \( s_1 \) and \( s_2 \), the oscillation frequencies are \( v_1 \) and \( v_2 \). If the same mass is attached to the two springs as shown in the figure, the oscillation frequency would be:
mass m is connected
A satellite moving around the Earth in a circular orbit has kinetic energy \( E \). Then, the minimum amount of energy to be added so that it escapes from the Earth is:
The elongation of a copper wire of cross-sectional area $3.5 \text{ mm}^2$, in the figure shown, is $$ Y_{\text{copper}} = 10 \times 10^{10} \, \text{Nm}^{-2} \quad \text{and} \quad g = 10 \, \text{m/s}^2 $$   
The elongation of a copper wire

In the given circuit, if the potential at point B is 24 V, the potential at point A is: 

Water is flowing in a streamline manner in a horizontal pipe. If the pressure at a point where cross-sectional area is \( 10 \) cm\(^2\) and velocity \( 1 \) m/s is \( 2000 \) Pa, then the pressure of water at another point where the cross-sectional area is \( 5 \) cm\(^2\) is:
A metal ball of mass 100 g at \( 20^\circ C \) is dropped in 200 ml of water at \( 80^\circ C \). If the resultant temperature is \( 70^\circ C \), then the ratio of specific heat of the metal to that of water is:
The efficiency of a heat engine that works between the temperatures where Celsius-Fahrenheit scales coincide and Kelvin-Fahrenheit scales coincide is (approximately):
Initially the pressure of 1 mole of an ideal gas is \( 10^5 \) Nm\(^2\) and its volume is 16 liters. When it is adiabatically compressed, its final volume is 2 liters. Work done on the gas is (molar specific heat at constant volume \( C_V = \frac{3R}{2} \)):
An ideal gas is taken around ABCA as shown in the P-V diagram. The work done during a cycle is:
An ideal gas is taken
The ratio of kinetic energy of a diatomic gas molecule at a high temperature to that of NTP is: