Question:

If the vertical component of the earth's magnetic field is 0.45 G at a location, and angle of dip is \( 60^\circ \), then magnetic field of earth at that location is:

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To calculate the total magnetic field when the vertical component and angle of dip are known, use the formula \( B_v = B \sin \delta \) and solve for \( B \).
Updated On: Mar 25, 2025
  • \( 0.26 \, {G} \)
  • \( 0.52 \, {G} \)
  • \( 0.3 \, {G} \)
  • \( 0.7 \, {G} \)
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The Correct Option is B

Solution and Explanation

We are given that the vertical component \( B_v = 0.45 \, {G} \) and the angle of dip \( \delta = 60^\circ \). The total magnetic field \( B \) is related to the vertical component \( B_v \) and the angle of dip \( \delta \) by the formula: \[ B_v = B \sin \delta. \] Step 1:
Substitute the given values into the equation: \[ 0.45 = B \sin 60^\circ. \] Since \( \sin 60^\circ = \frac{\sqrt{3}}{2} \), we have: \[ 0.45 = B \times \frac{\sqrt{3}}{2}. \] Step 2:
Solve for \( B \): \[ B = \frac{0.45 \times 2}{\sqrt{3}} = \frac{0.9}{\sqrt{3}}. \] Step 3:
Now calculate the value of \( B \): \[ B = \frac{0.9}{1.732} \approx 0.52 \, {G}. \] Thus, the total magnetic field at that location is \( 0.52 \, {G} \).
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