To form a complete monolayer of acetic acid on 1 g of charcoal, 100 mL of 0.5 M acetic acid was used. Some of the acetic acid remained unadsorbed. To neutralize the unadsorbed acetic acid, 40 mL of 1 M NaOH solution was required. If each molecule of acetic acid occupies \(P \times 10^{-23} \, m^2\) surface area on charcoal, the value of \(P\) is \_\_\_\_\_.
\text{[Use given data: Surface area of charcoal} = 1.5 \times 10^{2} \text{ m}^{2}\text{g}^{-1}; \text{Avogadro's number (N}_{\text{A}}) = 6.0 \times 10^{23} \text{mol}^{-1}]