The green bead indicates the presence of Fe3+. The number of unpaired electrons in Fe3+ is 5. The spin-only magnetic moment is given by:
\( \mu = \sqrt{n(n + 2)} \, \text{BM} \)
Substituting \( n = 5 \):
\( \mu = \sqrt{5(5 + 2)} = \sqrt{35} \approx 5.92 \, \text{BM} \)
Nearest integer = 6.
Among the following cations, the number of cations which will give characteristic precipitate in their identification tests with
\(K_4\)[Fe(CN)\(_6\)] is : \[ {Cu}^{2+}, \, {Fe}^{3+}, \, {Ba}^{2+}, \, {Ca}^{2+}, \, {NH}_4^+, \, {Mg}^{2+}, \, {Zn}^{2+} \]
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32