Limiting reagent is PbCl2.
Amount of Pb3(PO4)2 formed:
\( \text{mmol of Pb}_3(\text{PO}_4)_2 = \frac{\text{mmol of PbCl}_2 \text{ reacted}}{3} = 24 \text{ mmol} \)
LIST I | LIST II |
---|---|
A. 88 g of CO2 | I. 2 mol |
B. 6.023 × 1023 molecules of H2O | II. 1 mol |
C. 96 g of O2 | III. 6.023 × 1023 molecules |
D. 1 mol of any gas | IV. 3 mol |