The molecular weight of myoglobin can be calculated as:
\( \text{Molecular weight} = \frac{\text{Mass of Fe} \times 100}{\% \text{ of Fe}} = \frac{55.9 \times 100}{0.34} = 16441.18 \text{ g/mol}. \)
Arrange the following in decreasing order of number of molecules contained in:
(A) 16 g of \( O_2 \)
(B) 16 g of \( CO_2 \)
(C) 16 g of \( CO \)
(D) 16 g of \( H_2 \)
The molar mass of the water insoluble product formed from the fusion of chromite ore \(FeCr_2\text{O}_4\) with \(Na_2\text{CO}_3\) in presence of \(O_2\) is ....... g mol\(^{-1}\):
0.1 mole of compound S will weigh ...... g, (given the molar mass in g mol\(^{-1}\) C = 12, H = 1, O = 16)