Question:
The amount of agarose required to prepare 250 ππΏ of 0.8% agarose gel is _______ πππππ (rounded off to the nearest integer).
The amount of agarose required to prepare 250 ππΏ of 0.8% agarose gel is _______ πππππ (rounded off to the nearest integer).
Updated On: Jan 23, 2025
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Correct Answer: 2
Solution and Explanation
The weight of agarose required is calculated as:
\( \text{Weight} = \text{Concentration} \times \text{Volume}. \)
Substitute 0.8% (0.8 g/100 mL) and 250 mL:
\( \text{Weight} = 0.8 \times \frac{250}{100} = 2 \text{ g}. \)
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