In an electrochemical cell, the following reaction takes place :
$2\text{Cu}^{2+} (\text{aq}) + \text{Zn} (\text{s}) \rightarrow 2\text{Cu} (\text{s}) + \text{Zn}^{2+} (\text{aq})$
$E^\circ_{\text{cell}} = 1.28 \, \text{V}$
As the reaction progresses, what will happen to the overall voltage of the cell?