Question:

Williamson synthesis of preparing unsymmetrical ether is:

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The Williamson synthesis is best understood as an \text{S}N_2 reaction where a strong nucleophile attacks the electrophilic carbon in an alkyl halide.
Updated On: Jun 25, 2025
  • \text{S}N_1 \text{ reaction}
  • \text{S}N_2 \text{ reaction}
  • \text{Electrophilic addition reaction}
  • \text{Elimination reaction}
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The Correct Option is B

Solution and Explanation

The Williamson synthesis involves the preparation of unsymmetrical ethers through an \text{S}N_2 (nucleophilic substitution) mechanism. In this reaction, an alkoxide ion (\( \text{R-O}^- \)) reacts with a primary or secondary alkyl halide, resulting in the formation of an ether. The \text{S}N_2 mechanism occurs with a backside attack by the nucleophile on the carbon attached to the leaving group, leading to the formation of the ether. Therefore, the correct answer is (B) \text{S}N_2.
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