The Williamson synthesis involves the preparation of unsymmetrical ethers through an \text{S}N_2 (nucleophilic substitution) mechanism. In this reaction, an alkoxide ion (\( \text{R-O}^- \)) reacts with a primary or secondary alkyl halide, resulting in the formation of an ether. The \text{S}N_2 mechanism occurs with a backside attack by the nucleophile on the carbon attached to the leaving group, leading to the formation of the ether. Therefore, the correct answer is (B) \text{S}N_2.