Question:
In the Hinsberg method for separation of primary, secondary, and tertiary amines, the reagent used is:
In the Hinsberg method for separation of primary, secondary, and tertiary amines, the reagent used is:
Show Hint
In the Hinsberg test, primary amines form soluble sulfonamide salts, secondary amines form insoluble salts, and tertiary amines do not react with benzenesulfonyl chloride.
Updated On: Jun 25, 2025
- Nitrous acid
- CHCl₃ + aq. NaOH
- \(\text{C}_6\text{H}_5\text{SO}_2\text{Cl}\)
- HCl / ZnCl₂
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
The Hinsberg method is used for the separation of primary, secondary, and tertiary amines. The reagent used in this method is \(\text{C}_6\text{H}_5\text{SO}_2\text{Cl}\), commonly known as benzenesulfonyl chloride. This reagent reacts differently with primary, secondary, and tertiary amines, forming soluble or insoluble derivatives based on the amine type.
Was this answer helpful?
0
0
Top Questions on Organic Chemistry
- An alkene A with molecular formula C\(_6\)H\(_{10}\) on ozonolysis gives a mixture of two compounds B and C. Compound B gives positive Fehling test and also reacts with iodine and NaOH solution. Compound C does not give Fehling solution test but forms iodoform. Identify the compounds A, B, and C.
- CBSE CLASS XII - 2025
- Chemistry
- Organic Chemistry
Match the Compounds (List - I) with the appropriate Catalyst/Reagents (List - II) for their reduction into corresponding amines.
- JEE Main - 2025
- Chemistry
- Organic Chemistry
- In Dumas' method 292 mg of an organic compound released 50 mL of nitrogen gas ($ N_2 $) at 300 K temperature and 715 mm Hg pressure. The percentage composition of 'N' in the organic compound is _____ % (Nearest integer) (Aqueous tension at 300 K = 15 mm Hg)
- JEE Main - 2025
- Chemistry
- Organic Chemistry
Consider the following amino acid:
Which of the following options contain the correct structure of (A) and (B)?
- JEE Main - 2025
- Chemistry
- Organic Chemistry
- Isomeric hydrocarbons \( \rightarrow \) negative Baeyer's test (Molecular formula \( \text{C}_9\text{H}_{12} \)). The total number of isomers from above with four different non-aliphatic substitution sites is -
- JEE Main - 2025
- Chemistry
- Organic Chemistry
View More Questions
Questions Asked in CBSE CLASS XII exam
- Give reasons:
(a) Cooking is faster in a pressure cooker than in an open pan.
(b) On mixing liquid X and liquid Y, volume of the resulting solution decreases. What type of deviation from Raoult's law is shown by the resulting solution? What change in temperature would you observe after mixing liquids X and Y?- CBSE CLASS XII - 2025
- Solutions
- The electric field at a point in a region is given by \( \vec{E} = \alpha \frac{\hat{r}}{r^3} \), where \( \alpha \) is a constant and \( r \) is the distance of the point from the origin. The magnitude of potential of the point is:
- CBSE CLASS XII - 2025
- Electrostatics
- If \( \int \frac{1}{2x^2} \, dx = k \cdot 2x + C \), then \( k \) is equal to:
- CBSE CLASS XII - 2025
- Integration
- If \( \overrightarrow{a} + \overrightarrow{b} + \overrightarrow{c} = 0 \), \( |\overrightarrow{a}| = \sqrt{37} \), \( |\overrightarrow{b}| = 3 \), and \( |\overrightarrow{c}| = 4 \), then the angle between \( \overrightarrow{b} \) and \( \overrightarrow{c} \) is:
- Altima Ltd. invited applications for 2,00,000 equity shares of ₹ 10 at a premium of ₹ 4 per share. Amount payable:
On application and allotment – ₹ 7 (incl. ₹ 1 premium)
On first and final call – Balance.
Applications received for 2,40,000 shares. 30,000 rejected. Manvi allotted 4,000 shares failed to pay first and final call. Her shares were forfeited. These were reissued at ₹ 4 per share fully paid-up.
Pass journal entries in the books of Altima Ltd.- CBSE CLASS XII - 2025
- Accounting for Share Capital
View More Questions