Question:
Which of the following compounds would be hydrolyzed by aqueous KOH most easily?
Which of the following compounds would be hydrolyzed by aqueous KOH most easily?
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When hydrolyzing halides with aqueous KOH, compounds with alkene groups (as in option A) react more readily in substitution reactions due to their instability.
Updated On: Jun 25, 2025
- \(\text{CH}_2 = \text{CH} - \text{Br}\)
- \(\text{CH}_3 - \text{CH}_2 - \text{Br}\)
- \(\text{CH}_3 - \text{CH} - \text{CH}_3\)
- \(\text{CH}_2 = \text{CH} - \text{CH}_2 - \text{Br}\)
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The Correct Option is A
Solution and Explanation
The compound that would be hydrolyzed most easily by aqueous KOH is \(\text{CH}_2 = \text{CH} - \text{Br}\) (Option A). This compound is a vinyl halide, where the halide (\(\text{Br}\)) is attached to an alkene (\(\text{C} = \text{C}\)). Aqueous KOH typically undergoes nucleophilic substitution or elimination reactions, and in this case, the vinyl halide undergoes substitution more readily due to the instability of vinyl halides. Therefore, \(\text{CH}_2 = \text{CH} - \text{Br}\) would be hydrolyzed most easily compared to the other alkyl halides listed in the options.
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