If ∫ x49Tan−1(x50)(1+x100)\frac{x^{49} Tan^{-1} (x^{50})}{(1+x^{100})}(1+x100)x49Tan−1(x50)dx = k(Tan-1 (x50))2 + c, then k =
If ∫(log x)3 x5 dx = x6A\frac{x^6}{A}Ax6 [B(log x)3 + C(logx)2 + D(log x) - 1] + k and A,B,C,D are integers, then A - (B+C+D) =
∫dx(x2+1)(x2+4)=∫\frac{dx}{(x2+1) (x2+4)} =∫(x2+1)(x2+4)dx=
∫dx(x−1)34(x+2)54=∫\frac{dx}{(x-1)^{34} (x+2)^{\frac54}}=∫(x−1)34(x+2)45dx=
If order and degree of the differential equation corresponding to the family of curves y2 = 4a(x+a)(a is parameter) are m and n respectively, then m+n2 =
The general solution of the differential equation (x2 + 2)dy +2xydx = ex(x2+2)dx is
If l,m,n and a,b,c are direction cosines of two lines then
On differentiation if we get f (x,y)dy - g(x,y)dx = 0 from 2x2-3xy+y2+x+2y-8 = 0 then g(2,2)/f(1,1) =