To determine which equation correctly describes the change in molar conductivity with respect to concentration for a weak electrolyte, we need to consider the dissociation equilibrium and conductivity of weak electrolytes.
Molar conductivity (\(\Lambda_m\)) of an electrolyte is given by:
\(\Lambda_m = \frac{\kappa}{C}\)
where \(\kappa\) is the conductivity and \(C\) is the concentration.
The molar conductivity of a weak electrolyte at any concentration differs from its limiting molar conductivity (\(\Lambda_m^\circ\)) at infinite dilution. For weak electrolytes, as the concentration decreases, \(\Lambda_m\) approaches \(\Lambda_m^\circ\).
The relationship between molar conductivity and concentration for weak electrolytes is rather complex, and various models approximate it. A commonly used relationship involves the degree of dissociation, \(\alpha\), linked with the equilibrium constant (\(K_a\)). For a weak electrolyte:
\(\alpha = \frac{\Lambda_m}{\Lambda_m^\circ}\)
The equilibrium constant (\(K_a\)) can also be expressed as:
\(K_a = C\alpha^2 = C\left(\frac{\Lambda_m}{\Lambda_m^\circ}\right)^2\)
Rearranging gives us an expression reflective of the equation:
\(\Lambda_m^2 C - K_a \Lambda_m + K_a \Lambda_m^{\circ 2} = 0\)
This equation represents a quadratic relationship between molar conductivity, concentration, and the dissociation constant of a weak electrolyte.
Let's evaluate the given options:
Therefore, the correct answer is option \(\Lambda_m^2 C - K_a \Lambda_m + K_a \Lambda_m^{\circ 2} = 0\).
The relationship between molar conductivity $\Lambda_m$, molar conductivity at infinite dilution $\Lambda_m^\circ$, and concentration $C$ for a weak electrolyte can be derived from the dissociation equilibrium. The correct equation involves the dissociation constant $K_a$ and accounts for the variation of $\Lambda_m$ with concentration. For weak electrolytes, the molar conductivity $\Lambda_m$ is related to the degree of dissociation $\alpha$ as:
\[ \alpha = \frac{\Lambda_m}{\Lambda_m^\circ}. \]
The dissociation constant $K_a$ is expressed as:
\[ K_a = \frac{C\alpha^2}{1 - \alpha}. \]
Substituting $\alpha =\frac{\Lambda_m}{\Lambda_m^\circ}$ into the equation:
\[ K_a = \frac{C \left(\frac{\Lambda_m}{\Lambda_m^\circ}\right)^2}{1 - \frac{\Lambda_m}{\Lambda_m^\circ}}. \]
Simplifying and rearranging, the equation becomes:
\[ \Lambda_m^2 C - K_a \Lambda_m^{\circ 2} + K_a \Lambda_m \Lambda_m^\circ = 0. \]
This is the equation that correctly represents the relationship between molar conductivity, concentration, and dissociation constant for a weak electrolyte.
Final Answer: (1)

Consider the above electrochemical cell where a metal electrode (M) is undergoing redox reaction by forming $M^+$ ($M \to M^+ + e^-$). The cation $M^+$ is present in two different concentrations $c_1$ and $c_2$ as shown above. Which of the following statement is correct for generating a positive cell potential?
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]

