Question:

The number of complex numbers \( z \), satisfying \( |z| = 1 \) and \[ \left| \frac{z}{\overline{z}} + \frac{\overline{z}}{z} \right| = 1, \] is:

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When solving problems involving complex numbers on the unit circle, convert to polar form, use trigonometric identities, and check for distinct solutions in the given interval.
Updated On: Apr 30, 2025
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The Correct Option is D

Solution and Explanation

Step 1: Understand the Condition

We are given that \( |z| = 1 \). This means that the complex number \( z \) lies on the unit circle in the complex plane.

Any complex number on the unit circle can be written as: \( z = e^{i\theta} \), where \( \theta \) is the argument (angle) of \( z \).

Step 2: Use the Given Equation

The equation provided is:

\[ \left| \frac{z}{\overline{z}} + \frac{\overline{z}}{z} \right| = 1 \]

Step 3: Express \( z \) and \( \overline{z} \)

We know:

  • \( z = e^{i\theta} \)
  • \( \overline{z} = e^{-i\theta} \) (complex conjugate)

Now substitute into the equation:

\[ \frac{z}{\overline{z}} = \frac{e^{i\theta}}{e^{-i\theta}} = e^{2i\theta}, \quad \frac{\overline{z}}{z} = \frac{e^{-i\theta}}{e^{i\theta}} = e^{-2i\theta} \]

Step 4: Rewrite the Equation

Now the equation becomes:

\[ \left| e^{2i\theta} + e^{-2i\theta} \right| = 1 \]

Step 5: Use Euler’s Formula

We use the identity: \( e^{ix} + e^{-ix} = 2\cos x \)

Applying this, we get:

\[ e^{2i\theta} + e^{-2i\theta} = 2\cos(2\theta) \Rightarrow |2\cos(2\theta)| = 1 \]

Step 6: Solve for \( \cos(2\theta) \)

Divide both sides by 2:

\[ |\cos(2\theta)| = \frac{1}{2} \]

Step 7: Find All Possible \( 2\theta \) Values

The cosine of an angle is \( \pm \frac{1}{2} \) at the following values within \( 0 \leq 2\theta < 2\pi \):

  • \( 2\theta = \frac{\pi}{3}, \frac{2\pi}{3}, \frac{4\pi}{3}, \frac{5\pi}{3} \)
  • Also consider negative equivalents if needed: \( -\frac{\pi}{3}, -\frac{2\pi}{3}, -\frac{4\pi}{3}, -\frac{5\pi}{3} \)

So we have 8 distinct values of \( 2\theta \) that satisfy the condition.

Step 8: Find Corresponding \( \theta \) Values

Divide each \( 2\theta \) by 2 to get the angle \( \theta \):

  • \( \theta = \frac{\pi}{6}, \frac{\pi}{3}, \frac{2\pi}{3}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{4\pi}{3}, \frac{5\pi}{3}, \frac{11\pi}{6} \)

Final Answer:

There are 8 distinct complex numbers \( z \) that satisfy the given condition.

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