Question:
On a thin layer chromatographic plate, an organic compound moved by 3.5 cm, while the solvent moved by 5 cm. The retardation factor of the organic compound is \( \_\_\_\_ \times 10^{-1} \).
On a thin layer chromatographic plate, an organic compound moved by 3.5 cm, while the solvent moved by 5 cm. The retardation factor of the organic compound is \( \_\_\_\_ \times 10^{-1} \).
Updated On: Mar 21, 2025
Hide Solution
Verified By Collegedunia
Correct Answer: 7
Solution and Explanation
The retardation factor (Rf) is given by:
\(Rf =\frac{Distance\ travelled\ by\ sample/organic\ compound}{Distance\ travelled \ by \ solvent}\)
\(Rf=\frac{3.5}{5}=7 \times 10^{-1}\)
Was this answer helpful?
0
0
Top Questions on Chromatography and Its Principles
- Given below are two statements:
Statement (I): In partition chromatography, the stationary phase is a thin film of liquid present in the inert support.
Statement (II): In paper chromatography, the material of paper acts as a stationary phase.
In light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Chemistry
- Chromatography and Its Principles
- Chromatographic technique/s based on the principle of differential adsorption is/are
A. Column chromatography
B. Thin layer chromatography
C. Paper chromatography
Choose the most appropriate answer from the options given below:- JEE Main - 2024
- Chemistry
- Chromatography and Its Principles
- Using the given figure, the ratio of \(R_f\) values of sample A and sample C is x × 10–2. Value of x is __________.
- JEE Main - 2024
- Chemistry
- Chromatography and Its Principles
- Which of the following HPLC detectors is used as a bulk property or general-purpose detector?
- TANCET - 2024
- Pharmaceutical Technology
- Chromatography and Its Principles
- In reverse phase chromatography, the stationary phase is made by
- TANCET - 2024
- Pharmaceutical Technology
- Chromatography and Its Principles
View More Questions
Questions Asked in JEE Main exam
- In YDSE, light of intensity \( 4I \) and \( 9I \) passes through two slits respectively. Difference of maximum and minimum intensity of interference pattern is:
- JEE Main - 2025
- Wave optics
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
- JEE Main - 2025
- Differential Equations
Find the IUPAC name of the compound.
- JEE Main - 2025
- Aromaticity & chemistry of aromatic compounds
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32
- JEE Main - 2025
- Limits and Exponential Functions
- The integral \[ \int_0^\pi \frac{8x}{4\cos^2 x + \sin^2 x} \, dx \text{ is equal to:} \]
- JEE Main - 2025
- Trigonometric Functions
View More Questions