The \(R_f\) value in chromatography is given by:
\[R_f = \frac{\text{Distance traveled by the sample spot}}{\text{Distance traveled by the solvent front}}.\]
Step 1: Calculate \(R_f\) for sample \(A\)
For sample \(A\):
\[R_f(A) = \frac{\text{Distance traveled by sample } A}{\text{Distance traveled by solvent front}} = \frac{5}{12.5}.\]
\[R_f(A) = 0.4.\]
Step 2: Calculate \(R_f\) for sample \(C\)
For sample \(C\):
\[R_f(C) = \frac{\text{Distance traveled by sample } C}{\text{Distance traveled by solvent front}} = \frac{10}{12.5}.\]
\[R_f(C) = 0.8.\]
Step 3: Calculate the ratio of \(R_f\) values
The ratio of \(R_f\) values for sample \(A\) and sample \(C\) is:
\[\text{Ratio} = \frac{R_f(A)}{R_f(C)} = \frac{0.4}{0.8} = 0.5.\]
Expressing the ratio as \(x \times 10^{-2}\):
\[\text{Ratio} = 50 \times 10^{-2}.\]
Final Answer: \(x = 50\).
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is: