Question:

Let
\(S = \left\{z∈C : z^2+\overline{z} = 0 \right\}\). Then \(∑_{z∈S}(Re(z)+Im(z))\)
is equal to____.

Updated On: Aug 2, 2024
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Correct Answer: 0

Solution and Explanation

The correct answer is 0
\(∵ z^2+\overline{z} = 0\) Let \(z = x+iy\)
\(∴ x^2+y^2+2ixy+x-iy = 0\)
\((x^2-y^2+x)+i(2xy-y) = 0\)
\(∴ x^2+y^2 = 0\) and \((2x-1)y = 0\)
If \(x = +\frac{1}{2}\) then \(y = ±\frac{\sqrt3}{2}\)
And if y = 0 then x = 0, –1
\(∴\) \(z = \{ 0 + 0i, -1 + 0i, \frac{1}{2} + \frac{\sqrt{3}}{2}i, \frac{1}{2} - \frac{\sqrt{3}}{2}i \}\)
\(∴ ∑(R_e(z)+m(z)) = 0\)

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Concepts Used:

Complex Number

A Complex Number is written in the form

a + ib

where,

  • “a” is a real number
  • “b” is an imaginary number

The Complex Number consists of a symbol “i” which satisfies the condition i^2 = −1. Complex Numbers are mentioned as the extension of one-dimensional number lines. In a complex plane, a Complex Number indicated as a + bi is usually represented in the form of the point (a, b). We have to pay attention that a Complex Number with absolutely no real part, such as – i, -5i, etc, is called purely imaginary. Also, a Complex Number with perfectly no imaginary part is known as a real number.