In the circuit shown below, maximum Zener diode current will be ________ mA.
Correct Answer: 9
Solution and Explanation
\(i_s=\frac {60}{4×10^3}\)
\(i_s=15×10^{−3}\)
\(i_s=15\ mA\)
\(i_L=\frac {60}{10×10^3}\)
\(i_L=6\ mA\)
The maximum Zener diode current,
\(I_z=i_s–i_L\)
\(I_z = 15 mA - 6 mA\)
\(I_z=9 mA\)
So, the answer is \(9\ mA\).
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Concepts Used:
P-n Junction
A P-N junction is an interface or a boundary between two semiconductor material types, namely the p-type and the n-type, inside a semiconductor.
Biasing conditions for the p-n Junction Diode:
in p-n junction diode two operating regions are there:
- P-type
- N-type
There are three biasing conditions for p-n junction diode are as follows:
- Zero bias: When there is no external voltage applied to the p-n junction diode.
- Forward bias: P-type is connected to positive terminal of the voltage potential while n-type is connected to the negative terminal.
- Reverse bias: P-type is connected to negative terminal of the voltage potential while n-type is connected to the positive terminal.