A p-n junction diode is connected to a battery of emf 5.7 V in series with a resistor 5k \( \Omega \) such that it is forward biased. If the barrier potential of the diode is 0.7 V, neglecting the diode resistance, the current in the circuit is
- 1.14 mA
- 1 mA
- 1 A
- 1.14 A
The Correct Option is B
Solution and Explanation
Using Ohm's law, the current in the circuit is:
\(\ \ I = \frac{V - V_b}{R} = \frac{5.7 - 0.7}{5 \times 10^3} = 1 \text{mA}\)
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