If frequency can be represented as f = (radius)a (density)b (surface tension)c. Find a, b, c?
a = \(\frac{3}{2}\), b = \(\frac{1}{2}\), c = \(\frac{-1}{2}\)
a = \(\frac{-3}{2}\), b = \(\frac{-1}{2}\), c = \(\frac{1}{2}\)
a = \(\frac{-3}{2}\), b = \(\frac{1}{2}\), c = \(\frac{-1}{2}\)
a = \(\frac{1}{2}\), b = \(\frac{3}{2}\), c = \(\frac{-1}{2}\)
M0L0T–1 = La(ML–3)b(MT–2)c
M0L0T–1 = LaMbL–3b McT–2c
Equivalent the power of MLT
M \(\Rightarrow\) 0 = b + c
L \(\Rightarrow\) 0 = a – 3b
T \(\Rightarrow\) –1 = – 2c
a = \(\frac{-3}{2}\), b = \(\frac{-1}{2}\), c = \(\frac{1}{2}\)
Match the LIST-I with LIST-II
| LIST-I | LIST-II | ||
| A. | Boltzmann constant | I. | \( \text{ML}^2\text{T}^{-1} \) |
| B. | Coefficient of viscosity | II. | \( \text{MLT}^{-3}\text{K}^{-1} \) |
| C. | Planck's constant | III. | \( \text{ML}^2\text{T}^{-2}\text{K}^{-1} \) |
| D. | Thermal conductivity | IV. | \( \text{ML}^{-1}\text{T}^{-1} \) |
Choose the correct answer from the options given below :
The ratio of the power of a light source \( S_1 \) to that of the light source \( S_2 \) is 2. \( S_1 \) is emitting \( 2 \times 10^{15} \) photons per second at 600 nm. If the wavelength of the source \( S_2 \) is 300 nm, then the number of photons per second emitted by \( S_2 \) is ________________ \( \times 10^{14} \).
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to:

The amount of energy required to increase the liquid's surface area by one unit area is known as surface tension. In other words, it is a property of the liquid surface to resist force.
Surface tension is defined as,
The ratio of the surface force F to the length L along which the force acts.
Mathematically, the surface tension formula can be expressed as follows:
T=F/L
Where,
Read More: Detergents and Surface Tension
The SI unit of Surface Tension is Newton per Meter or N/m.