Question:
Consider the given plots of vapor pressure (VP) vs temperature (T/K). Which amongst the following options is the correct graphical representation showing \( \Delta T_f \) depression in the freezing point of solvent in a solution?
Consider the given plots of vapor pressure (VP) vs temperature (T/K). Which amongst the following options is the correct graphical representation showing \( \Delta T_f \) depression in the freezing point of solvent in a solution?
Show Hint
In freezing point depression, the presence of solute decreases the vapor pressure of the solvent, resulting in a lower freezing point. This is a colligative property that depends on the amount of solute, not its identity.
Updated On: Mar 17, 2025
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Freezing point depression occurs when a solute is added to a solvent, lowering its freezing point.
The correct graph shows the vapor pressure curve of the solution below that of the pure solvent, with the freezing point of the solution occurring at a lower temperature.
The correct representation is \( \text{Option (3)} \), where the freezing point depression (\( \Delta T_f \)) is clearly shown, with the solution curve below the solvent curve.
Thus, the correct answer is: \( \boxed{(3)} \).
The correct graph shows the vapor pressure curve of the solution below that of the pure solvent, with the freezing point of the solution occurring at a lower temperature.
The correct representation is \( \text{Option (3)} \), where the freezing point depression (\( \Delta T_f \)) is clearly shown, with the solution curve below the solvent curve.
Thus, the correct answer is: \( \boxed{(3)} \).
Was this answer helpful?
0
0
Top Questions on Colligative Properties
- Arrange the following solutions in order of their increasing boiling points.
(i) \(10^{-4}\) M NaCl
(ii) \(10^{-4}\) M Urea
(iii) \(10^{-3}\) M NaCl
(iv) \(10^{-2}\) M NaCl- JEE Main - 2025
- Chemistry
- Colligative Properties
- CrCl\(_3\).xNH\(_3\) can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558°C. Assuming 100\% ionization of this complex and coordination number of Cr is 6, the complex will be:
- JEE Main - 2025
- Chemistry
- Colligative Properties
A solution of glucose (molar mass = 180 g mol\(^{-1}\)) in water has a boiling point of 100.20°C. Calculate the freezing point of the same solution. Molal constants for water \(K_f\) and \(K_b\) are 1.86 K kg mol\(^{-1}\) and 0.512 K kg mol\(^{-1}\) respectively.
- CBSE CLASS XII - 2025
- Chemistry
- Colligative Properties
(A) Give reasons: (a) Cooking is faster in a pressure cooker than in an open pan. (b) On mixing liquid X and liquid Y, volume of the resulting solution decreases. What type of deviation from Raoult's law is shown by the resulting solution? What change in temperature would you observe after mixing liquids X and Y?
- CBSE CLASS XII - 2025
- Chemistry
- Colligative Properties
In case of association, abnormal molar mass of solute will:
- CBSE CLASS XII - 2025
- Chemistry
- Colligative Properties
View More Questions
Questions Asked in JEE Main exam
- Let \( M \) denote the set of all real matrices of order 3 x 3 and let \( S = \{-3, -2, -1, 1, 2\} \). Let
\( S_1 = \{A = [a_{ij}] \in M : A = A^T \text{ and } a_{ij} \in S, \forall i, j\} \),
\( S_2 = \{A = [a_{ij}] \in M : A = -A^T \text{ and } a_{ij} \in S, \forall i, j\} \),
\( S_3 = \{A = [a_{ij}] \in M : a_{11} + a_{22} + a_{33} = 0 \text{ and } a_{ij} \in S, \forall i, j\} \).
If \(n(S_1 \cup S_2 \cup S_3) = 125\), then \( \alpha \) equals:- JEE Main - 2025
- Linear Algebra
- Consider a long thin conducting wire carrying a uniform current \( I \). A particle having mass \( M \) and charge \( q \) is released at a distance \( a \) from the wire with a speed \( v_0 \) along the direction of current in the wire. The particle gets attracted to the wire due to magnetic force. The particle turns round when it is at distance \( x \) from the wire. The value of \( x \) is:
- JEE Main - 2025
- Magnetic Field
- A thin prism \( P_1 \) with angle \( 4^\circ \) made of glass having refractive index 1.54 is combined with another thin prism \( P_2 \) made of glass having refractive index 1.72 to get dispersion without deviation. The angle of the prism \( P_2 \) in degrees is:
- JEE Main - 2025
- Ray optics and optical instruments
- A hemispherical vessel is completely filled with a liquid of refractive index \( \mu \). A small coin is kept at the lowest point \( O \) of the vessel as shown in the figure. The minimum value of the refractive index of the liquid so that a person can see the coin from point \( E \) (at the level of the vessel) is:
- JEE Main - 2025
- Ray optics and optical instruments
- A particle of mass \( m \) and charge \( q \) is fastened to one end \( A \) of a massless string having equilibrium length \( l \), whose other end is fixed at point \( O \). The whole system is placed on a frictionless horizontal plane and is initially at rest. If a uniform electric field is switched on along the direction as shown in the figure, then the speed of the particle when it crosses the x-axis is:
- JEE Main - 2025
- Electric charges and fields
View More Questions