Question:
Among the given pair of vectors, the resultant of two vectors can never be 3 units. The vectors are
Among the given pair of vectors, the resultant of two vectors can never be 3 units. The vectors are
Updated On: Dec 26, 2024
- 1 unit and 2 units
- 2 units and 5 units
- 3 units and 6 units
- 4 units and 8 units
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The magnitude of the resultant of two vectors lies between the range of their sum and the difference. For vectors of magnitudes 4 units and 8 units, the possible resultant must be between:
\(\ \ |8 - 4| = 4 \text{units} \quad \text{and} \quad 8 + 4 = 12 \text{units}.\)
Was this answer helpful?
0
0
Top Questions on Vectors
- Let \( L_1: \frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4} \) and \( L_2: \frac{x-2}{3} = \frac{y-4}{4} = \frac{z-5}{5} \) be two lines. Then which of the following points lies on the line of the shortest distance between \( L_1 \) and \( L_2 \)?
- Let \( \vec{c} \) be the projection vector of \( \mathbf{b} = \lambda \hat{i} + 4 \hat{k}, \lambda > 0 \), on the vector \( \vec{a} = \hat{i} + 2 \hat{j} + 2 \hat{k} \). If \( |\vec{a} + \vec{c}| = 7 \), then the area of the parallelogram formed by the vectors \( \vec{b} \) and \( \vec{c} \) is:
- Let \( \vec{a} = 2\hat{i} - \hat{j} + 3\hat{k} \), \( \vec{b} = 3\hat{i} - 5\hat{j} + \hat{k} \), and \( \vec{c} \) be a vector such that \( \vec{a} \times \vec{c} = \vec{a} \times \vec{b} \) and \( (\vec{a} + \vec{c}) \cdot (\vec{b} + \vec{c}) = 168 \). Then the maximum value of \( |\vec{c}|^2 \) is:
- Let \( L_1 : \frac{x - 1}{1} = \frac{y - 2}{-1} = \frac{z - 1}{-1} \) and \( L_2 : \frac{x + 1}{1} = \frac{y - 2}{2} = \frac{z - 2}{2} \) be two lines. Let \( L_3 \) be a line passing through the point \( (\alpha, \beta, \gamma) \) and be perpendicular to both \( L_1 \) and \( L_2 \). If \( L_3 \) intersects \( L_1 \) where \( 5x - 11y - 8z = 1 \), then \( 5x - 11y - 8z \) equals:
- Let \( \vec{a} = \hat{i} + 2\hat{j} + \hat{k} \) and \( \vec{b} = 2\hat{i} + 7\hat{j} + 3\hat{k} \). Let \( L_1 : \vec{r} = (-\hat{i} + 2\hat{j} + \hat{k}) + \lambda \vec{a}, \lambda \in {R} \) and \( L_2 : \vec{r} = (\hat{j} + \hat{k}) + \mu \vec{b}, \mu \in \mathbb{R} \) be two lines. If the line \( L_3 \) passes through the point of intersection of \( L_1 \) and \( L_2 \), and is parallel to \( \vec{a} + \vec{b} \), then \( L_3 \) passes through the point:
View More Questions
Questions Asked in KCET exam
- The electric current flowing through a given conductor varies with time as shown in the graph below. The number of free electrons which flow through a given cross-section of the conductor in the time interval \( 0 \leq t \leq 20 \, \text{s} \) is
- KCET - 2024
- Current electricity
- A die is thrown 10 times. The probability that an odd number will come up at least once is:
- KCET - 2024
- Probability
- The incorrect statement about the Hall-Heroult process is:
- KCET - 2024
- General Principles and Processes of Isolation of Elements
- Corner points of the feasible region for an LPP are $(0, 2), (3, 0), (6, 0), (6, 8)$ and $(0, 5)$. Let $z = 4x + 6y$ be the objective function. The minimum value of $z$ occurs at:
- KCET - 2024
- Linear Programming Problem
- If a random variable $X$ follows the binomial distribution with parameters $n = 5$, $p$, and $P(X = 2) = 9P(X = 3)$, then $p$ is equal to:
- KCET - 2024
- binomial distribution
View More Questions