Match the following:
In the following, \( [x] \) denotes the greatest integer less than or equal to \( x \). 
Choose the correct answer from the options given below:
Let's analyze each expression and match it with the correct option:
- (a) \( x|x| \): The function \( x|x| \) is continuous everywhere, but not differentiable at \( x = 0 \) because the derivative has a discontinuity at \( x = 0 \). Thus, it is not differentiable at \( x = 0 \), corresponding to (iv).
- (b) \( \sqrt{|x|} \): The function \( \sqrt{|x|} \) is continuous but not differentiable at \( x = 0 \). The absolute value inside the square root introduces a cusp at \( x = 0 \), so it is not differentiable at that point. Thus, the correct matching is (ii), meaning the function is differentiable in \( (-1, 1) \), except at \( x = 0 \).
- (c) \( x + |x| \): The function \( x + |x| \) is continuous and differentiable everywhere because it is linear in both the negative and positive domains of \( x \). Thus, it is strictly increasing in \( (-1, 1) \), corresponding to (iii).
- (d) \( |x - 1| + |x + 1| \): The function \( |x - 1| + |x + 1| \) is continuous but not differentiable at \( x = 0 \) because the absolute value functions cause a corner at that point. Thus, it is not differentiable at at least one point in \( (-1, 1) \), corresponding to (iv). Thus, the correct matching is: \[ \text{a - iii, b - ii, c - i, d - iii} \] Therefore, the correct answer is option 3.
Let the function, \(f(x)\) = \(\begin{cases} -3ax^2 - 2, & x < 1 \\a^2 + bx, & x \geq 1 \end{cases}\) Be differentiable for all \( x \in \mathbb{R} \), where \( a > 1 \), \( b \in \mathbb{R} \). If the area of the region enclosed by \( y = f(x) \) and the line \( y = -20 \) is \( \alpha + \beta\sqrt{3} \), where \( \alpha, \beta \in \mathbb{Z} \), then the value of \( \alpha + \beta \) is:
Match List-I with List-II and select the correct option: 