A wire X of length 50 cm carrying a current of 2 A is placed parallel to a long wire Y of length 5 m. The wire Y carries a current of 3 A. The distance between two wires is 5 cm and currents flow in the same direction. The force acting on the wire Y is
A wire X of length 50 cm carrying a current of 2 A is placed parallel to a long wire Y of length 5 m. The wire Y carries a current of 3 A. The distance between two wires is 5 cm and currents flow in the same direction. The force acting on the wire Y is
- 1.2 × 10–5 N directed towards wire X
- 1.2 × 10–4 N directed away from wire X
- 1.2 × 10–4 N directed towards wire X
- 2.4 × 10–5 N directed towards wire X
The Correct Option is A
Solution and Explanation
FXY = FYX = F
\(F=\frac{μ_0I_2}{2πr}I_1(l)\)
\(=\frac{4π×10^{−7}×3×2×[50×10^{−2}]}{2π(5×10^{−2})}\)
= 1.2 × 10–5 N
So, the correct option is (A): 1.2 × 10–5 N directed towards wire X
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Concepts Used:
Electric Current
Defining Electric Current
It is the rate of flow of electrons in a conductor. SI Unit - Ampere (A).
Electrons are negatively charged particles hence when they move a number of charges moves.
Note:- The ability of a particular substance to conduct electricity depends on the number of electrons that are able to move . Some of the materials allow current to flow better than others.
What is an Electromotive Force?
If a force acts on electrons to make them move in a particular direction, then up to some extent random motion of the electrons will be eliminated. An overall movement in one direction. The force which acts on the electrons to move them in a certain direction is known as electromotive force and its quantity is known as voltage and is measured in V.