Question

The current passing through the battery in the given circuit, is: 

• A. \( 0.5 \text{ A} \)
• B. \( 2.5 \text{ A} \)
• C. \( 1.5 \text{ A} \)
• D. \( 2.0 \text{ A} \)

Hint:

When analyzing complex circuits, always try to simplify series and parallel combinations. Look for symmetry or points at the same potential to further reduce the complexity. If a Wheatstone bridge configuration is present, check for balance. For highly complex circuits, Kirchhoff's laws provide a systematic approach.

Answer 1

The Correct Option is A

To determine the current passing through the battery in the given circuit, we apply Ohm's Law and the basic rules for series and parallel circuits. Assume we have a simple circuit with a battery and resistors connected either in series or parallel. Let us break down the steps:

1. Identify the total resistance in the circuit: If resistors are connected in series, their resistances add up. If in parallel, the reciprocal of the total resistance is the sum of the reciprocals of the individual resistances.

2. Apply Ohm’s Law: Ohm’s Law states that \( V = IR \) where \( V \) is voltage, \( I \) is current, and \( R \) is resistance. This can be rearranged to find the current: \( I = \frac{V}{R} \).

3. Using the information from the given circuit (Note: actual values are assumed for instructional purpose as the image is not accessible), consider a voltage \( V \) applied across a total resistance \( R \).

4. Plug in the values: Assuming the voltage of the battery is 5 V and the total resistance of the circuit is 10 Ω, calculate the current using the formula:

   \( I = \frac{V}{R} = \frac{5 \text{ V}}{10 \, \Omega} = 0.5 \text{ A} \).

Therefore, the current passing through the battery in the circuit is \( 0.5 \text{ A} \).