Question

0.5 g of an organic compound on combustion gave 1.46 g of $ CO_2 $ and 0.9 g of $ H_2O $. The percentage of carbon in the compound is ______ (Nearest integer) $\text{(Given : Molar mass (in g mol}^{-1}\text{ C : 12, H : 1, O : 16})$

Hint:

During combustion of an organic compound, all the carbon present in the compound is converted to \( CO_2 \). Use the molar mass ratio to find the mass of carbon in the \( CO_2 \) produced and then calculate the percentage of carbon in the organic compound.

Answer 1

Correct Answer: 80

Organic Compound → CO₂

Applying POAC on ‘C’

Option (mole) of ‘C’ in compound = $n_{\text{CO}_2} \times 1$

So mass of ‘C’ in compound = $\dfrac{1.46}{44} \times 12$

So, % of ‘C’ in compound =
\[ \dfrac{1.46}{44} \times \dfrac{12}{0.5} \times 100 \]
= 79.63