Given below are two statements:
Statement (I):
are isomeric compounds.
Statement (II): are functional group isomers.
In the light of the above statements, choose the correct answer from the options given below:
- Statement (I) is incorrect because the compounds shown are not isomeric. Isomerism refers to different compounds with the same molecular formula but different structures or functional groups.
- Statement (II) is also incorrect because \( {NH}_2 \) and \( {NH} \) are not functional group isomers.
Functional group isomers are compounds that have the same molecular formula but differ in their functional groups.
\( {NH}_2 \) is an amine group, while \( {NH} \) is an imine group, but they are not functional group isomers.
Therefore, both statements are false.
Draw the possible isomers of:
\[ [ \text{Co}(\text{en})_2\text{Cl}_2 ]^+ \]
The incorrect statements regarding geometrical isomerism are:
(A) Propene shows geometrical isomerism.
(B) Trans isomer has identical atoms/groups on the opposite sides of the double bond.
(C) Cis-but-2-ene has higher dipole moment than trans-but-2-ene.
(D) 2-methylbut-2-ene shows two geometrical isomers.
(E) Trans-isomer has lower melting point than cis isomer.
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $