Let \(\Delta, \nabla \in\{\Lambda, V\}\) be such that \(( p \rightarrow q ) \Delta( p \nabla q )\) is a tautology. Then
The shortest distance between the lines \(x+1=2 y=-12 z\) and \(x=y+2=6 z-6\) is
The mean and variance of 7 observations are 8 and 16, respectively. If one observation 14 is omitted and a and b are respectively the mean and variance of the remaining 6 observations, then \(a+3b−5\) is equal to
For a free body diagram shown in the figure, the four forces are applied in the ' $x$ ' and ' $y$ ' directions What additional force must be applied and at what angle with positive $x$-axis so that the net acceleration of body is zero?
A block of mass 100 gm is placed on a smooth surface, moves with the acceleration of a=2x, the change in kinetic energy can be given as \((\frac {x^n}{10})\), find the value of n.