Let \(\Delta, \nabla \in\{\Lambda, V\}\) be such that \(( p \rightarrow q ) \Delta( p \nabla q )\) is a tautology. Then
For the given expression to be a tautology, every possible valuation of \(p\) and \(q\) must make the expression true. Since \(p \to q\) is equivalent to \(\neg p \lor q\), the expression simplifies as:
\( (\neg p \lor q) \land (p \lor q) \)
Using distributive laws:
\( (\neg p \land p) \lor (\neg p \land q) \lor (p \land q) \lor (q \land q) \)
Simplifying further, knowing \(\neg p \land p\) is always false:
\( (\neg p \land q) \lor (p \land q) \lor q = q \)
Hence, for the expression to be a tautology, it must always evaluate to true, which is the case when \(\land\) and \(\lor\) are defined such that the final result of any expression involving these operators is always true.
The correct answer is (B) : \(\Delta=V, \nabla=V\)
Given (p→q)Δ(p∇q)
Option I Δ=∧,∇=∨
Hence, it is tautology.
Option 4Δ=∧,∇=∧
The respective values of \( |\vec{a}| \) and} \( |\vec{b}| \), if given \[ (\vec{a} - \vec{b}) \cdot (\vec{a} + \vec{b}) = 512 \quad \text{and} \quad |\vec{a}| = 3 |\vec{b}|, \] are:
In general, vectors are used in Maths and Science and are categorized into 10 different types of vectors such as:-