120
6
12
We are tasked with finding the number of four-digit numbers that satisfy the following conditions:
The first digit must ensure the number is between 5000 and 10000. Therefore, it must be \( 5 \), \( 7 \), or \( 9 \). This gives us 3 choices for the first digit.
Once the first digit is chosen, there are 4 remaining digits in the set \( \{1, 3, 5, 7, 9\} \) (excluding the chosen first digit). The second digit can then be any one of these 4 digits, giving 4 choices for the second digit. For the third digit, we are left with 3 choices (the remaining digits after the first two have been selected). Similarly, for the fourth digit, there are 2 remaining choices.
The total number of valid numbers is given by the product of choices for each position:
\[ 3 \times 4 \times 3 \times 2 = 72 \]
Thus, there are 72 four-digit numbers that satisfy the given conditions.
The correct answer is (A) : 72
Numbers between 5000&10000
Using digits 1,3,5,7,9

In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).

A permutation is an arrangement of multiple objects in a particular order taken a few or all at a time. The formula for permutation is as follows:
\(^nP_r = \frac{n!}{(n-r)!}\)
nPr = permutation
n = total number of objects
r = number of objects selected