The correct answer is : \(\frac{4}{9}\)
The radii of the Bohr orbits in hydrogen atom are given by the formula:
\(r_n = \frac{(n^2 * h^2 * ε₀) } {(π * m * e^2)}\)
where r_n is the radius of the nth Bohr orbit, n is the principal quantum number, h is the Planck's constant, ε₀ is the permittivity of free space, m is the mass of the electron, and e is the charge of the electron.
The ratio of radii of the second and third Bohr orbits can be calculated by substituting n=2 and n=3 in the above formula and taking the ratio:
\(\frac{r_2}{ r_3} = \frac{\frac{(2^2 * h^2 * ε₀)}{(π * m * e^2)}}{ \frac{(3^2 * h^2 * ε₀)}{ (π * m * e^2)}}\)
\(= \frac{4}{9}\)
Therefore, the ratio of radii of second and third Bohr orbit of H-atoms is \(\frac{4}{9}\)
Match List-I with List-II: List-I
Niels Bohr introduced the atomic Hydrogen model in 1913. He described it as a positively charged nucleus, comprised of protons and neutrons, surrounded by a negatively charged electron cloud. In the model, electrons orbit the nucleus in atomic shells. The atom is held together by electrostatic forces between the positive nucleus and negative surroundings.
Read More: Bohr's Model of Hydrogen Atom
A hydrogen-like atom consists of a tiny positively-charged nucleus and an electron revolving around the nucleus in a stable circular orbit.
If 'e,' 'm,' and 'v' be the charge, mass, and velocity of the electron respectively, 'r' be the radius of the orbit, and Z be the atomic number, the equation for the radii of the permitted orbits is given by r = n2 xr1, where 'n' is the principal quantum number, and r1 is the least allowed radius for a hydrogen atom, known as Bohr's radius having a value of 0.53 Å.
The Bohr Model was an important step in the development of atomic theory. However, it has several limitations.