The filament of a light bulb has surface area \(64\, mm ^{2}\) The filament can be considered as a black body at temperature \(2500\, K\) emitting radiation like a point source when viewed from far At night the light bulb is observed from a distance of \(100 \,m\). Assume the pupil of the eyes of the observer to be circular with radius \(3 \,mm\) Then (Take Stefan-Boltzmann constant =\(567 \times 10^{-8}\), \(Wm ^{-2} K ^{-4}\), Wien's displacement constant =\(290 \times 10^{-3} \),\(m - K\), Planck's constant =\(663 \times 10^{-34} \,Js\), speed of light in vacuum =\(300 \times 108\, ms ^{-1} )\)