
Step 1: Identify the least count (L.C) of the Vernier calipers
The least count is the smallest measurement that can be accurately read using the instrument. It is given as:
L.C = 0.01 cm
This means the Vernier calipers can measure up to one-hundredth of a centimeter accurately.
Step 2: Account for the systematic error
Sometimes, the instrument may have a zero error or a systematic error due to misalignment or calibration issues. In this case, it is given that there is an error equivalent to 4 least counts:
Error = 4 × L.C = 4 × 0.01 cm = 0.04 cm
This error needs to be added to the observed measurement to obtain the true value.
Step 3: Determine the observed reading
The observed measurement from the Vernier calipers consists of two parts:
- Main scale reading = 3.1 cm
- Vernier scale reading = 1 division = 1 × 0.01 cm = 0.01 cm
So, Observed reading = 3.1 cm + 0.01 cm = 3.11 cm
Step 4: Add the error to get the corrected value
To get the correct diameter of the sphere, the error is added to the observed value:
Corrected diameter = 3.11 cm + 0.04 cm = 3.15 cm
Final Answer:
Therefore, the correct diameter of the sphere is 3.15 cm
Correct option: Option (C)
Match the LIST-I with LIST-II
| LIST-I | LIST-II | ||
| A. | Boltzmann constant | I. | \( \text{ML}^2\text{T}^{-1} \) |
| B. | Coefficient of viscosity | II. | \( \text{MLT}^{-3}\text{K}^{-1} \) |
| C. | Planck's constant | III. | \( \text{ML}^2\text{T}^{-2}\text{K}^{-1} \) |
| D. | Thermal conductivity | IV. | \( \text{ML}^{-1}\text{T}^{-1} \) |
Choose the correct answer from the options given below :
The ratio of the power of a light source \( S_1 \) to that of the light source \( S_2 \) is 2. \( S_1 \) is emitting \( 2 \times 10^{15} \) photons per second at 600 nm. If the wavelength of the source \( S_2 \) is 300 nm, then the number of photons per second emitted by \( S_2 \) is ________________ \( \times 10^{14} \).
Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.
A unit of a physical quantity is an arbitrarily chosen standard that is broadly acknowledged by the society and in terms of which other quantities of similar nature may be measured.
The process of measurement is basically a comparison process. To measure a physical quantity, we have to find out how many times a standard amount of that physical quantity is present in the quantity being measured. The number thus obtained is known as the magnitude and the standard chosen is called the unit of the physical quantity.
Read More: Fundamental and Derived Units of Measurement
The units defined for the fundamental quantities are called fundamental units.
The units of all other physical quantities which are derived from the fundamental units are called the derived units.