The given physical quantity is defined as:
\( \vec{S} = \frac{\vec{E} \times \vec{B}}{\mu_0} \)
Where \( \vec{E} \) is the electric field, \( \vec{B} \) is the magnetic field, and \( \mu_0 \) is the permeability of free space. We are asked to find the dimensions of \( \vec{S} \) and compare it to the dimensions of other physical quantities.
Step 1: Analyzing the dimensions of each term
The electric field \( \vec{E} \) has dimensions of force per unit charge, which can be expressed as:
\( [E] = \frac{ML}{T^3I} \)
The magnetic field \( \vec{B} \) has dimensions of force per unit charge per velocity, which can be written as:
\( [B] = \frac{M}{T^2I} \)
The permeability of free space \( \mu_0 \) has dimensions:
\( [\mu_0] = \frac{M}{A^2T^2} \)
Step 2: Calculating the dimensions of \( \vec{S} \)
The dimensions of \( \vec{S} \) are given by:
\( [\vec{S}] = \frac{[E] \times [B]}{[\mu_0]} \)
Substituting the dimensions of \( \vec{E} \), \( \vec{B} \), and \( \mu_0 \):
\( [\vec{S}] = \frac{\left( \frac{ML}{T^3I} \right) \times \left( \frac{M}{T^2I} \right)}{\frac{M}{A^2T^2}} = \frac{M^2L}{T^5I^2} \times \frac{A^2T^2}{M} = \frac{ML^2}{T^3I^2A^2} \)
Step 3: Identifying the quantity with the same dimensions
The dimensions of \( \vec{S} \) are the same as the dimensions of:
\( \frac{\text{Power}}{\text{Area}} \)
This is because power has dimensions of \( \frac{ML^2}{T^3I} \) and area has dimensions of \( L^2 \), so \( \frac{\text{Power}}{\text{Area}} \) has the same dimensions as \( \vec{S} \).
Final Answer:
\( \frac{\text{Power}}{\text{Area}} \)
Two identical concave mirrors each of focal length $ f $ are facing each other as shown. A glass slab of thickness $ t $ and refractive index $ n_0 $ is placed equidistant from both mirrors on the principal axis. A monochromatic point source $ S $ is placed at the center of the slab. For the image to be formed on $ S $ itself, which of the following distances between the two mirrors is/are correct:
The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.
The waves that are produced when an electric field comes into contact with a magnetic field are known as Electromagnetic Waves or EM waves. The constitution of an oscillating magnetic field and electric fields gives rise to electromagnetic waves.
Electromagnetic waves can be grouped according to the direction of disturbance in them and according to the range of their frequency. Recall that a wave transfers energy from one point to another point in space. That means there are two things going on: the disturbance that defines a wave, and the propagation of wave. In this context the waves are grouped into the following two categories: