Question:

The calculated spin only magnetic moments of $\left[ Cr \left( NH _{3}\right)_{6}\right]^{3+}$ and $\left[ CuF _{6}\right]^{3-}$ in BM, respectively, are
(Atomic number of $Cr$ and $Cu$ are $24$ and $29$ , respectively)

Updated On: Aug 19, 2024
  • 3.87 and 2.84
  • 4.90 and 1.73
  • 3.87 and 1.73
  • 4.90 and 2.84
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The Correct Option is A

Solution and Explanation

[Cr(NH3)6]3+ = Cr3+
Cr3+ = 3d3 4s0

It has 3 unpaired electrons
\(\mu = n \sqrt{n+2}\) BM
\(\mu = \sqrt[3]{3+2}\) BM
μ = 3.87 BM

[CuF6]3- = Cu+3
Cu+3 = 3d8 4s0

It has 2 unpaired electrons
μ = \(2\sqrt{2+2}\) BM
= 2.84 BM
The correct answer is option (A): 3.87 and 2.84

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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.