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BITSAT
List of top Questions asked in BITSAT
If a function \( f: \mathbb{R} \setminus \{1\} \rightarrow \mathbb{R} \setminus \{m\} \) is defined by \( f(x) = \frac{x+3}{x-2} \), then \( \frac{3}{l} + 2m = \)
BITSAT - 2024
BITSAT
Mathematics
Algebra
If \( y = \tan^{-1}\left( \frac{\sqrt{x} - x}{1 + x^{3/2}} \right) \), then \( y'(1) \) is equal to:
BITSAT - 2024
BITSAT
Mathematics
Application of derivatives
The population \( p(t) \) at time \( t \) of a certain mouse species satisfies the differential equation:
\[ \frac{d p(t)}{dt} = 0.5p(t) - 450. \]
If \( p(0) = 850 \), then the time at which the population becomes zero is:
BITSAT - 2024
BITSAT
Mathematics
Application of derivatives
If the angle made by the tangent at the point \((x_0, y_0)\) on the curve \(x = 12(t + \sin t \cos t)\), \(y = 12(1 + \sin t)^2\), with \(0<t<\frac{\pi}{2}\), with the positive x-axis is \(\frac{\pi}{3}\), then \(y_0\) is equal to:
BITSAT - 2024
BITSAT
Mathematics
Application of derivatives
At \( x = \frac{\pi^2}{4} \), \( \frac{d}{dx} \left( \tan^{-1}(\cos\sqrt{x}) + \sec^{-1}(e^x) \right) = \)
BITSAT - 2024
BITSAT
Mathematics
Application of derivatives
Consider the function \( f(x) = \frac{|x-1|
{x^2} \). Then \( f(x) \) is:}
BITSAT - 2024
BITSAT
Mathematics
integral
If
\( x\sqrt{1 + y} + y\sqrt{1 + x} = 0 \),
then find
\( \frac{dy}{dx} \).
BITSAT - 2024
BITSAT
Mathematics
Application of derivatives
Given that \( f(x) = \sin x + \cos x \) and \( g(x) = x^2 - 1 \), find the conditions under which \( g(f(x)) \) is invertible.
BITSAT - 2024
BITSAT
Mathematics
Trigonometry
The maximum volume (in cu. units) of the cylinder which can be inscribed in a sphere of radius 12 units is:
BITSAT - 2024
BITSAT
Mathematics
Application of derivatives
The maximum area of a rectangle inscribed in a circle of diameter \( R \) is:
BITSAT - 2024
BITSAT
Mathematics
circle
The function f: R\(\rightarrow\) R is defined by
\[ f(x) = \frac{x}{\sqrt{1 + x^2}} \]
is:
BITSAT - 2024
BITSAT
Mathematics
Algebra
The function
\[ f(x) = \frac{\cos x}{\left\lfloor \frac{2x}{\pi} \right\rfloor + \frac{1}{2}}, \]
where \( x \) is not an integral multiple of \( \pi \) and \( \lfloor \cdot \rfloor \) denotes the greatest integer function, is:
BITSAT - 2024
BITSAT
Mathematics
integral
Evaluate the integral:
\[ \int \sqrt{x + \sqrt{x^2 + 2}} \, dx. \]
BITSAT - 2024
BITSAT
Mathematics
integral
The point of inflexion for the curve \(y = (x - a)^n\), where \(n\) is odd integer and \(n \ge 3\), is:
BITSAT - 2024
BITSAT
Mathematics
Application of derivatives
The domain of the real-valued function
\[ f(x) = \sqrt{\frac{2x^2 - 7x + 5}{3x^2 - 5x - 2}} \]
is:
BITSAT - 2024
BITSAT
Mathematics
Algebra
Evaluate the following limit:
\[ \lim_{n \to \infty} \prod_{r=3}^n \frac{r^3 - 8}{r^3 + 8}. \]
BITSAT - 2024
BITSAT
Mathematics
limits and derivatives
Evaluate the integral:
\[ \int \frac{x^2 (x \sec^2 x + \tan x)}{(x \tan x + 1)^2} dx \]
BITSAT - 2024
BITSAT
Mathematics
integral
The value of \( \int_0^{\frac{\pi}{2}} \frac{\sin\left( \frac{\pi}{4} + x \right) + \sin\left( \frac{3\pi}{4} + x \right)}{\cos x + \sin x} \, dx \) is:
BITSAT - 2024
BITSAT
Mathematics
integral
The line \(y = mx\) bisects the area enclosed by lines \(x = 0\), \(y = 0\), and \(x = \frac{3}{2}\) and the curve \(y = 1 + 4x - x^2\). Then, the value of \(m\) is:
BITSAT - 2024
BITSAT
Mathematics
Application of derivatives
Evaluate the integral:
\[ \int_{5}^{9} \frac{\log 3x^2}{\log 3x^2 + \log (588 - 84x + 3x^2)} dx \]
BITSAT - 2024
BITSAT
Mathematics
integral
A ball falling freely from a height of \( 4.9 \) m/s hits a horizontal surface. If \( e = \frac{3}{4} \), then the ball will hit the surface the second time after:
BITSAT - 2024
BITSAT
Physics
thermal properties of matter
The acceptor level of a p-type semiconductor is \( 6 \) eV. The maximum wavelength of light which can create a hole would be: Given \( hc = 1242 \) eV nm.
BITSAT - 2024
BITSAT
Physics
thermal properties of matter
A spherical ball of mass \( 20 \) kg is stationary at the top of a hill of height \( 100 \) m. It rolls down a smooth surface to the ground, then climbs up another hill of height \( 30 \) m and finally rolls down to a horizontal base at a height of \( 20 \) m above the ground. The velocity attained by the ball is:
BITSAT - 2024
BITSAT
Physics
Reflection Of Light By Spherical Mirrors
In normal adjustment, for a refracting telescope, the distance between the objective and eyepiece is 30 cm. The focal length of the objective, when the angular magnification of the telescope is 2, will be:
BITSAT - 2024
BITSAT
Physics
thermal properties of matter
The complex with the highest magnitude of crystal field splitting energy (\(\Delta_0\)) is:
BITSAT - 2024
BITSAT
Chemistry
thermal properties of matter
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