To solve the problem, we need to identify the reagent that can convert an aldehyde to a primary alcohol.
1. Understanding the Reaction:
- Aldehydes can be reduced to primary alcohols by reducing agents.
- Oxidizing agents typically convert aldehydes to carboxylic acids.
- Some reagents oxidize aldehydes without reducing them.
2. Analysis of Each Reagent:
- PCC (Pyridinium chlorochromate): An oxidizing agent that oxidizes primary alcohols to aldehydes but does not reduce aldehydes.
- $NaBH_4$ (Sodium borohydride): A mild reducing agent that reduces aldehydes to primary alcohols.
- $KMnO_4$ (Potassium permanganate): A strong oxidizing agent, converts aldehydes to carboxylic acids.
- $HNO_3$ (Nitric acid): An oxidizing agent, not a reducing agent.
3. Conclusion:
Only $NaBH_4$ is capable of reducing aldehydes to primary alcohols.
Final Answer:
The correct reagent is $ {NaBH_4} $ (Sodium borohydride).
The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____. 
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80
For the reaction \( A + B \to C \), the rate law is found to be \( \text{rate} = k[A]^2[B] \). If the concentration of \( A \) is doubled and \( B \) is halved, by what factor does the rate change?