Step 1: Use the work-energy principle.
The work required to stop the body equals the loss in kinetic energy.
Step 2: Calculate initial kinetic energy.
\[ KE = \frac{1}{2} m v^2 = \frac{1}{2} \cdot 2 \cdot (5)^2 = 25 \text{ J} \]
Step 3: Final velocity is 0, so all kinetic energy is lost.
Hence, work done to stop the body = \( \boxed{25 \text{ J}} \)
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
The scientist's theory was initially met with _________, but later gained widespread acclaim after consistent experimental validation.