1-Bromopropane undergoes nucleophilic substitution with hydroxide ion (\(OH^-\)) to form an alcohol. The reaction follows an \(S_N2\) mechanism because \(1^\circ\) halides undergo \(S_N2\) substitution. The reaction is: \[ \text{CH}_3\text{CH}_2\text{CH}_2\text{Br} + OH^- \rightarrow \text{CH}_3\text{CH}_2\text{CH}_2\text{OH}. \] Thus, the major product is propan-1-ol. The correct answer is: \[ \boxed{\text{Propan-1-ol}}. \]